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两步完成DP
$dp[i][j] = \lbrace_{max(dp[i+1][j],dp[i][j-1])—if(s[i] != s[j])}^{dp[i+1][j-1]+2---------if(s[i] == s[j]} $ 有一个问题是;AC的c++代码是通过python改过的,但是Python是通不过的,很奇怪,d[2][3]在其中一步中会自己修改值,我很不理解,是它有bug,还是我的代码有bug。。。求看的人帮忙解答一下哦//C++ AC代码class Solution { public: int longestPalindromeSubseq(string s) { int l = s.length(); int dp[1001][1001]; memset(dp,0,sizeof(dp)); for(int i = 0;i < l;i++) for(int j = 0;j < l;j++) dp[i][j] = 0; for(int i = l-1;i >= 0;i--){ dp[i][i] = 1; for(int j = i+1;j < l;j++){ if (s[i] == s[j]) if (j-1 > i+1) dp[i][j] = dp[i+1][j-1] + 2; else if (j-1 == i+1) dp[i][j] = 3; else dp[i][j] = 2; else dp[i][j] = max(dp[i+1][j] , dp[i][j-1]); } } return dp[0][l-1]; }};
# pythonclass Solution(object): def longestPalindromeSubseq(self, s): """ :type s: str :rtype: int """ l = len(s) dp = [[]*1001]*1001 for i in range(0,l): for j in range(0,l): dp[i].append(0) for i in range(l,-1,-1): dp[i][i] = 1 for j in range(i+1,l): print(i,'--',j) if s[i] is s[j]:#慢慢往下减可以不 if j-1 > i+1: dp[i][j] = dp[i+1][j-1] + 2 print('dp[',i,'][',j,'] = ',dp[i][j],i+1,j-1,dp[i+1][j-1],'----2--1--') print(dp[2][3],'----2--1--') elif j-1 == i+1: dp[i][j] = 3 print('dp[',i,'][',j,'] = ',dp[i][j],'----2--2--') print(dp[2][3],'----2--2--') else: dp[i][j] = 2 print('dp[',i,'][',j,'] = ',dp[i][j],'----2--3--') print(dp[2][3],'----2--3--') else: dp[i][j] = max(dp[i+1][j] , dp[i][j-1]) print('dp[',i,'][',j,'] = ',dp[i][j],'----max----') print(dp[2][3],'----max----') return dp[0][l-1]
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